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Diameter of centre crankshaft under flywheel at max torque Formula

GoDiameter of centre crankshaft under flywheel at max torque given bending and torsional moment Formula

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Diameter of Shaft Under Flywheel is the diameter, of the part of the crankshaft under the flywheel, the distance across the shaft that passes through the center of the shaft is 2R (twice the radius). Check FAQs

d s = {((\frac{16}{π \cdot τ}) \cdot \sqrt{{(R b \cdot c g)}^{2} + {(P t \cdot r)}^{2}})}^{\frac{1}{3}}

d_s - Diameter of Shaft Under Flywheel?τ - Shear Stress in Crankshaft Under Flywheel?R_b - Resultant Reaction on CrankShaft Bearing?c_g - Centre Crankshaft Bearing Gap From Flywheel?P_t - Tangential Force at Crank Pin?r - Distance Between Crank Pin And Crankshaft?π - Archimedes' constant?

Diameter of centre crankshaft under flywheel at max torque Example

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Here is how the Diameter of centre crankshaft under flywheel at max torque equation looks like with Values.

Here is how the Diameter of centre crankshaft under flywheel at max torque equation looks like with Units.

Here is how the Diameter of centre crankshaft under flywheel at max torque equation looks like.

61.453 = {((\frac{16}{3.1416 \cdot 15}) \cdot \sqrt{{(1200 \cdot 200)}^{2} + {(8000 \cdot 80)}^{2}})}^{\frac{1}{3}}

61.453mm = {((\frac{16}{3.1416 \cdot 15N/mm²}) \cdot \sqrt{{(1200N \cdot 200mm)}^{2} + {(8000N \cdot 80mm)}^{2}})}^{\frac{1}{3}}

61.453 = {((\frac{16}{3.1416 \cdot 15}) \cdot \sqrt{{(1200 \cdot 200)}^{2} + {(8000 \cdot 80)}^{2}})}^{\frac{1}{3}}

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Diameter of centre crankshaft under flywheel at max torque Solution

Follow our step by step solution on how to calculate Diameter of centre crankshaft under flywheel at max torque?

FIRST Step Consider the formula

d s = {((\frac{16}{π \cdot τ}) \cdot \sqrt{{(R b \cdot c g)}^{2} + {(P t \cdot r)}^{2}})}^{\frac{1}{3}}

Next Step Substitute values of Variables

∴

d s = {((\frac{16}{π \cdot 15N/mm²}) \cdot \sqrt{{(1200N \cdot 200mm)}^{2} + {(8000N \cdot 80mm)}^{2}})}^{\frac{1}{3}}

Next Step Substitute values of Constants

∴

d s = {((\frac{16}{3.1416 \cdot 15N/mm²}) \cdot \sqrt{{(1200N \cdot 200mm)}^{2} + {(8000N \cdot 80mm)}^{2}})}^{\frac{1}{3}}

Next Step Convert Units

∴

d s = {((\frac{16}{3.1416 \cdot 1.5E+7Pa}) \cdot \sqrt{{(1200N \cdot 0.2m)}^{2} + {(8000N \cdot 0.08m)}^{2}})}^{\frac{1}{3}}

Next Step Prepare to Evaluate

∴

d s = {((\frac{16}{3.1416 \cdot 1.5E+7}) \cdot \sqrt{{(1200 \cdot 0.2)}^{2} + {(8000 \cdot 0.08)}^{2}})}^{\frac{1}{3}}

Next Step Evaluate

∴

d s = 0.0614530472065787m

Next Step Convert to Output's Unit

∴

d s = 61.4530472065787mm

LAST Step Rounding Answer

∴

d s = 61.453mm

Diameter of centre crankshaft under flywheel at max torque Formula Elements

Variables

Constants

Functions

Diameter of Shaft Under Flywheel

Diameter of Shaft Under Flywheel is the diameter, of the part of the crankshaft under the flywheel, the distance across the shaft that passes through the center of the shaft is 2R (twice the radius).

Symbol: d_s

Measurement: LengthUnit: mm