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Torsional shear stress in side-crankshaft below flywheel for max torque Formula

GoTorsional shear stress in side-crankshaft below flywheel for max torque given moments Formula

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Shear Stress in Crankshaft Under Flywheel is the amount of shear stress (causes deformation by slippage along plane parallel to the imposed stress) at the crankshaft part under flywheel. Check FAQs

τ = \frac{16}{π \cdot {D s}^{3}} \cdot \sqrt{{M b v}^{2} + {M b h}^{2} + {(P t \cdot r)}^{2}}

τ - Shear Stress in Crankshaft Under Flywheel?D_s - Diameter of Shaft Under Flywheel?M_bv - Vertical Bending Moment in Shaft Under Flywheel?M_bh - Horizontal Bending Moment in Shaft Under Flywheel?P_t - Tangential Force at Crank Pin?r - Distance Between Crank Pin And Crankshaft?π - Archimedes' constant?

Torsional shear stress in side-crankshaft below flywheel for max torque Example

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Here is how the Torsional shear stress in side-crankshaft below flywheel for max torque equation looks like with Values.

Here is how the Torsional shear stress in side-crankshaft below flywheel for max torque equation looks like with Units.

Here is how the Torsional shear stress in side-crankshaft below flywheel for max torque equation looks like.

10.7736 = \frac{16}{3.1416 \cdot {35.4321}^{3}} \cdot \sqrt{25000^{2} + 82400^{2} + {(3613.665 \cdot 10.5)}^{2}}

10.7736N/mm² = \frac{16}{3.1416 \cdot {35.4321mm}^{3}} \cdot \sqrt{{25000N*mm}^{2} + {82400N*mm}^{2} + {(3613.665N \cdot 10.5mm)}^{2}}

10.7736 = \frac{16}{3.1416 \cdot {35.4321}^{3}} \cdot \sqrt{25000^{2} + 82400^{2} + {(3613.665 \cdot 10.5)}^{2}}

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Torsional shear stress in side-crankshaft below flywheel for max torque Solution

Follow our step by step solution on how to calculate Torsional shear stress in side-crankshaft below flywheel for max torque?

FIRST Step Consider the formula

τ = \frac{16}{π \cdot {D s}^{3}} \cdot \sqrt{{M b v}^{2} + {M b h}^{2} + {(P t \cdot r)}^{2}}

Next Step Substitute values of Variables

∴

τ = \frac{16}{π \cdot {35.4321mm}^{3}} \cdot \sqrt{{25000N*mm}^{2} + {82400N*mm}^{2} + {(3613.665N \cdot 10.5mm)}^{2}}

Next Step Substitute values of Constants

∴

τ = \frac{16}{3.1416 \cdot {35.4321mm}^{3}} \cdot \sqrt{{25000N*mm}^{2} + {82400N*mm}^{2} + {(3613.665N \cdot 10.5mm)}^{2}}

Next Step Convert Units

∴

τ = \frac{16}{3.1416 \cdot {0.0354m}^{3}} \cdot \sqrt{{25N*m}^{2} + {82.4N*m}^{2} + {(3613.665N \cdot 0.0105m)}^{2}}

Next Step Prepare to Evaluate

∴

τ = \frac{16}{3.1416 \cdot {0.0354}^{3}} \cdot \sqrt{25^{2} + {82.4}^{2} + {(3613.665 \cdot 0.0105)}^{2}}

Next Step Evaluate

∴

τ = 10773568.0928511Pa

Next Step Convert to Output's Unit

∴

τ = 10.7735680928511N/mm²

LAST Step Rounding Answer

∴

τ = 10.7736N/mm²

Torsional shear stress in side-crankshaft below flywheel for max torque Formula Elements

Variables

Constants

Functions

Shear Stress in Crankshaft Under Flywheel

Shear Stress in Crankshaft Under Flywheel is the amount of shear stress (causes deformation by slippage along plane parallel to the imposed stress) at the crankshaft part under flywheel.

Symbol: τ

Measurement: StressUnit: N/mm²