Principle Shear Stress Maximum Shear Stress Theory of Failure Formula

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Maximum Shear Stress in Shaft From ASME is the maximum amount of shear stress arising due to shear forces and is calculated using ASME code for shaft design. Check FAQs

𝜏' max = \frac{16}{π \cdot {d'}^{3}} \cdot \sqrt{{(M' s \cdot k t')}^{2} + {(k b' \cdot M s)}^{2}}

𝜏'_max - Maximum Shear Stress in Shaft From ASME?d' - Diameter of Shaft From ASME?M'_s - Torsional Moment in Shaft?k_t' - Combined Shock Fatigue Factor of Torsion Moment?k_b' - Combined Shock Fatigue Factor of Bending Moment?M_s - Bending Moment in Shaft?π - Archimedes' constant?

Principle Shear Stress Maximum Shear Stress Theory of Failure Example

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Here is how the Principle Shear Stress Maximum Shear Stress Theory of Failure equation looks like with Values.

Here is how the Principle Shear Stress Maximum Shear Stress Theory of Failure equation looks like with Units.

Here is how the Principle Shear Stress Maximum Shear Stress Theory of Failure equation looks like.

150.51 = \frac{16}{3.1416 \cdot 48^{3}} \cdot \sqrt{{(330000 \cdot 1.3)}^{2} + {(1.8 \cdot 1.8E+6)}^{2}}

150.51N/mm² = \frac{16}{3.1416 \cdot {48mm}^{3}} \cdot \sqrt{{(330000N*mm \cdot 1.3)}^{2} + {(1.8 \cdot 1.8E+6N*mm)}^{2}}

150.51 = \frac{16}{3.1416 \cdot 48^{3}} \cdot \sqrt{{(330000 \cdot 1.3)}^{2} + {(1.8 \cdot 1.8E+6)}^{2}}

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Principle Shear Stress Maximum Shear Stress Theory of Failure Solution

Follow our step by step solution on how to calculate Principle Shear Stress Maximum Shear Stress Theory of Failure?

FIRST Step Consider the formula

𝜏' max = \frac{16}{π \cdot {d'}^{3}} \cdot \sqrt{{(M' s \cdot k t')}^{2} + {(k b' \cdot M s)}^{2}}

Next Step Substitute values of Variables

∴

𝜏' max = \frac{16}{π \cdot {48mm}^{3}} \cdot \sqrt{{(330000N*mm \cdot 1.3)}^{2} + {(1.8 \cdot 1.8E+6N*mm)}^{2}}

Next Step Substitute values of Constants

∴

𝜏' max = \frac{16}{3.1416 \cdot {48mm}^{3}} \cdot \sqrt{{(330000N*mm \cdot 1.3)}^{2} + {(1.8 \cdot 1.8E+6N*mm)}^{2}}

Next Step Convert Units

∴

𝜏' max = \frac{16}{3.1416 \cdot {0.048m}^{3}} \cdot \sqrt{{(330N*m \cdot 1.3)}^{2} + {(1.8 \cdot 1800N*m)}^{2}}

Next Step Prepare to Evaluate

∴

𝜏' max = \frac{16}{3.1416 \cdot {0.048}^{3}} \cdot \sqrt{{(330 \cdot 1.3)}^{2} + {(1.8 \cdot 1800)}^{2}}

Next Step Evaluate

∴

𝜏' max = 150510010.712373Pa

Next Step Convert to Output's Unit

∴

𝜏' max = 150.510010712373N/mm²

LAST Step Rounding Answer

∴

𝜏' max = 150.51N/mm²

Principle Shear Stress Maximum Shear Stress Theory of Failure Formula Elements

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Constants

Functions

Maximum Shear Stress in Shaft From ASME

Maximum Shear Stress in Shaft From ASME is the maximum amount of shear stress arising due to shear forces and is calculated using ASME code for shaft design.

Symbol: 𝜏'_max

Measurement: StressUnit: N/mm²