Total Surface Area of Hollow Frustum Formula

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Total Surface Area of Hollow Frustum is the total quantity of plane occupied by the surface of the entire Hollow Frustum. Check FAQs

TSA = (\frac{n}{4} \cdot (S Long Outer + S Short Outer) \cdot \sqrt{({(\cot (\frac{π}{n}))}^{2} \cdot {(S Long Outer - S Short Outer)}^{2}) + (4 \cdot h^{2})}) + (\frac{n}{4} \cdot (S Long Inner + S Short Inner) \cdot \sqrt{({(\cot (\frac{π}{n}))}^{2} \cdot {(S Long Inner - S Short Inner)}^{2}) + (4 \cdot h^{2})}) + (\frac{n \cdot ({S Long Outer}^{2} - {S Long Inner}^{2})}{4 \cdot \tan (\frac{π}{n})}) + (\frac{n \cdot ({S Short Outer}^{2} - {S Short Inner}^{2})}{4 \cdot \tan (\frac{π}{n})})

TSA - Total Surface Area of Hollow Frustum?n - Number of Base Vertices of Hollow Frustum?S_{Long Outer} - Long Outer Side of Hollow Frustum?S_{Short Outer} - Short Outer Side of Hollow Frustum?h - Height of Hollow Frustum?S_{Long Inner} - Long Inner Side of Hollow Frustum?S_{Short Inner} - Short Inner Side of Hollow Frustum?π - Archimedes' constant?

Total Surface Area of Hollow Frustum Example

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Here is how the Total Surface Area of Hollow Frustum equation looks like with Values.

Here is how the Total Surface Area of Hollow Frustum equation looks like with Units.

Here is how the Total Surface Area of Hollow Frustum equation looks like.

646 = (\frac{4}{4} \cdot (14 + 9) \cdot \sqrt{({(\cot (\frac{3.1416}{4}))}^{2} \cdot {(14 - 9)}^{2}) + (4 \cdot 6^{2})}) + (\frac{4}{4} \cdot (10 + 5) \cdot \sqrt{({(\cot (\frac{3.1416}{4}))}^{2} \cdot {(10 - 5)}^{2}) + (4 \cdot 6^{2})}) + (\frac{4 \cdot (14^{2} - 10^{2})}{4 \cdot \tan (\frac{3.1416}{4})}) + (\frac{4 \cdot (9^{2} - 5^{2})}{4 \cdot \tan (\frac{3.1416}{4})})

646m² = (\frac{4}{4} \cdot (14m + 9m) \cdot \sqrt{({(\cot (\frac{3.1416}{4}))}^{2} \cdot {(14m - 9m)}^{2}) + (4 \cdot {6m}^{2})}) + (\frac{4}{4} \cdot (10m + 5m) \cdot \sqrt{({(\cot (\frac{3.1416}{4}))}^{2} \cdot {(10m - 5m)}^{2}) + (4 \cdot {6m}^{2})}) + (\frac{4 \cdot ({14m}^{2} - {10m}^{2})}{4 \cdot \tan (\frac{3.1416}{4})}) + (\frac{4 \cdot ({9m}^{2} - {5m}^{2})}{4 \cdot \tan (\frac{3.1416}{4})})

646 = (\frac{4}{4} \cdot (14 + 9) \cdot \sqrt{({(\cot (\frac{3.1416}{4}))}^{2} \cdot {(14 - 9)}^{2}) + (4 \cdot 6^{2})}) + (\frac{4}{4} \cdot (10 + 5) \cdot \sqrt{({(\cot (\frac{3.1416}{4}))}^{2} \cdot {(10 - 5)}^{2}) + (4 \cdot 6^{2})}) + (\frac{4 \cdot (14^{2} - 10^{2})}{4 \cdot \tan (\frac{3.1416}{4})}) + (\frac{4 \cdot (9^{2} - 5^{2})}{4 \cdot \tan (\frac{3.1416}{4})})

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Total Surface Area of Hollow Frustum Solution

Follow our step by step solution on how to calculate Total Surface Area of Hollow Frustum?

FIRST Step Consider the formula

TSA = (\frac{n}{4} \cdot (S Long Outer + S Short Outer) \cdot \sqrt{({(\cot (\frac{π}{n}))}^{2} \cdot {(S Long Outer - S Short Outer)}^{2}) + (4 \cdot h^{2})}) + (\frac{n}{4} \cdot (S Long Inner + S Short Inner) \cdot \sqrt{({(\cot (\frac{π}{n}))}^{2} \cdot {(S Long Inner - S Short Inner)}^{2}) + (4 \cdot h^{2})}) + (\frac{n \cdot ({S Long Outer}^{2} - {S Long Inner}^{2})}{4 \cdot \tan (\frac{π}{n})}) + (\frac{n \cdot ({S Short Outer}^{2} - {S Short Inner}^{2})}{4 \cdot \tan (\frac{π}{n})})

Next Step Substitute values of Variables

∴

TSA = (\frac{4}{4} \cdot (14m + 9m) \cdot \sqrt{({(\cot (\frac{π}{4}))}^{2} \cdot {(14m - 9m)}^{2}) + (4 \cdot {6m}^{2})}) + (\frac{4}{4} \cdot (10m + 5m) \cdot \sqrt{({(\cot (\frac{π}{4}))}^{2} \cdot {(10m - 5m)}^{2}) + (4 \cdot {6m}^{2})}) + (\frac{4 \cdot ({14m}^{2} - {10m}^{2})}{4 \cdot \tan (\frac{π}{4})}) + (\frac{4 \cdot ({9m}^{2} - {5m}^{2})}{4 \cdot \tan (\frac{π}{4})})

Next Step Substitute values of Constants

∴

TSA = (\frac{4}{4} \cdot (14m + 9m) \cdot \sqrt{({(\cot (\frac{3.1416}{4}))}^{2} \cdot {(14m - 9m)}^{2}) + (4 \cdot {6m}^{2})}) + (\frac{4}{4} \cdot (10m + 5m) \cdot \sqrt{({(\cot (\frac{3.1416}{4}))}^{2} \cdot {(10m - 5m)}^{2}) + (4 \cdot {6m}^{2})}) + (\frac{4 \cdot ({14m}^{2} - {10m}^{2})}{4 \cdot \tan (\frac{3.1416}{4})}) + (\frac{4 \cdot ({9m}^{2} - {5m}^{2})}{4 \cdot \tan (\frac{3.1416}{4})})

Next Step Prepare to Evaluate

∴

TSA = (\frac{4}{4} \cdot (14 + 9) \cdot \sqrt{({(\cot (\frac{3.1416}{4}))}^{2} \cdot {(14 - 9)}^{2}) + (4 \cdot 6^{2})}) + (\frac{4}{4} \cdot (10 + 5) \cdot \sqrt{({(\cot (\frac{3.1416}{4}))}^{2} \cdot {(10 - 5)}^{2}) + (4 \cdot 6^{2})}) + (\frac{4 \cdot (14^{2} - 10^{2})}{4 \cdot \tan (\frac{3.1416}{4})}) + (\frac{4 \cdot (9^{2} - 5^{2})}{4 \cdot \tan (\frac{3.1416}{4})})

LAST Step Evaluate

∴

TSA = 646m²

Total Surface Area of Hollow Frustum Formula Elements

Variables

Constants

Functions

Total Surface Area of Hollow Frustum

Total Surface Area of Hollow Frustum is the total quantity of plane occupied by the surface of the entire Hollow Frustum.

Symbol: TSA

Measurement: AreaUnit: m²