Shear stress in crankweb of centre crankshaft for max torque given reaction on bearing1 Formula

GoShear stress in crankweb of centre crankshaft for max torque given torsional moment Formula

GoShear stress in crankweb of centre crankshaft for max torque given polar section modulus Formula

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Shear Stress in Crankweb is the amount of shear stress (causes deformation by slippage along plane parallel to the imposed stress) in the crankweb. Check FAQs

T = \frac{4.5}{w \cdot t^{2}} \cdot ((R h1 \cdot (b 1 + \frac{l c}{2})) - (P t \cdot \frac{l c}{2}))

T - Shear Stress in Crankweb?w - Width of Crank Web?t - Thickness of Crank Web?R_h1 - Horizontal Force at Bearing1 by Tangential Force?b₁ - Centre Crankshaft Bearing1 Gap from CrankPinCentre?l_c - Length of Crank Pin?P_t - Tangential Force at Crank Pin?

Shear stress in crankweb of centre crankshaft for max torque given reaction on bearing1 Example

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Here is how the Shear stress in crankweb of centre crankshaft for max torque given reaction on bearing1 equation looks like with Values.

Here is how the Shear stress in crankweb of centre crankshaft for max torque given reaction on bearing1 equation looks like with Units.

Here is how the Shear stress in crankweb of centre crankshaft for max torque given reaction on bearing1 equation looks like.

18.9549 = \frac{4.5}{65 \cdot 40^{2}} \cdot ((3443.57 \cdot (155 + \frac{42}{2})) - (8000 \cdot \frac{42}{2}))

18.9549N/mm² = \frac{4.5}{65mm \cdot {40mm}^{2}} \cdot ((3443.57N \cdot (155mm + \frac{42mm}{2})) - (8000N \cdot \frac{42mm}{2}))

18.9549 = \frac{4.5}{65 \cdot 40^{2}} \cdot ((3443.57 \cdot (155 + \frac{42}{2})) - (8000 \cdot \frac{42}{2}))

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Shear stress in crankweb of centre crankshaft for max torque given reaction on bearing1 Solution

Follow our step by step solution on how to calculate Shear stress in crankweb of centre crankshaft for max torque given reaction on bearing1?

FIRST Step Consider the formula

T = \frac{4.5}{w \cdot t^{2}} \cdot ((R h1 \cdot (b 1 + \frac{l c}{2})) - (P t \cdot \frac{l c}{2}))

Next Step Substitute values of Variables

∴

T = \frac{4.5}{65mm \cdot {40mm}^{2}} \cdot ((3443.57N \cdot (155mm + \frac{42mm}{2})) - (8000N \cdot \frac{42mm}{2}))

Next Step Convert Units

∴

T = \frac{4.5}{0.065m \cdot {0.04m}^{2}} \cdot ((3443.57N \cdot (0.155m + \frac{0.042m}{2})) - (8000N \cdot \frac{0.042m}{2}))

Next Step Prepare to Evaluate

∴

T = \frac{4.5}{0.065 \cdot {0.04}^{2}} \cdot ((3443.57 \cdot (0.155 + \frac{0.042}{2})) - (8000 \cdot \frac{0.042}{2}))

Next Step Evaluate

∴

T = 18954879.2307692Pa

Next Step Convert to Output's Unit

∴

T = 18.9548792307692N/mm²

LAST Step Rounding Answer

∴

T = 18.9549N/mm²

Shear stress in crankweb of centre crankshaft for max torque given reaction on bearing1 Formula Elements

Variables

Shear Stress in Crankweb

Shear Stress in Crankweb is the amount of shear stress (causes deformation by slippage along plane parallel to the imposed stress) in the crankweb.

Symbol: T

Measurement: StressUnit: N/mm²