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Volume of Wasted Sludge Per Day given Ultimate BOD Formula

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GoVolume of Wasted Sludge Per Day given Oxygen Required in Aeration Tank Formula

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GoVolume of Wasted Sludge Per Day given Oxygen Demand of Biomass Formula

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Volume of Wasted Sludge is the amount of sludge that is removed or wasted from a wastewater treatment process on a daily basis. Check FAQs

Q w' = \frac{(\frac{Q s \cdot (Q i - Q)}{\frac{BOD5}{BOD u}}) - O 2}{1.42 \cdot X}

Q_w' - Volume of Wasted Sludge?Q_s - Sewage Discharge?Q_i - Influent BOD?Q - Effluent BOD?BOD5 - 5 Days BOD?BOD^u - Ultimate BOD?O₂ - Theoretical Oxygen Requirement?X - MLSS?

Volume of Wasted Sludge Per Day given Ultimate BOD Example

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Here is how the Volume of Wasted Sludge Per Day given Ultimate BOD equation looks like with Values.

Here is how the Volume of Wasted Sludge Per Day given Ultimate BOD equation looks like with Units.

Here is how the Volume of Wasted Sludge Per Day given Ultimate BOD equation looks like.

0.1105 = \frac{(\frac{10 \cdot (13.2 - 0.4)}{\frac{1.36}{2}}) - 2.5}{1.42 \cdot 1200}

0.1105m³/s = \frac{(\frac{10m³/s \cdot (13.2mg/L - 0.4mg/L)}{\frac{1.36mg/L}{2mg/L}}) - 2.5mg/d}{1.42 \cdot 1200mg/L}

0.1105 = \frac{(\frac{10 \cdot (13.2 - 0.4)}{\frac{1.36}{2}}) - 2.5}{1.42 \cdot 1200}

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Volume of Wasted Sludge Per Day given Ultimate BOD Solution

Follow our step by step solution on how to calculate Volume of Wasted Sludge Per Day given Ultimate BOD?

FIRST Step Consider the formula

Q w' = \frac{(\frac{Q s \cdot (Q i - Q)}{\frac{BOD5}{BOD u}}) - O 2}{1.42 \cdot X}

Next Step Substitute values of Variables

∴

Q w' = \frac{(\frac{10m³/s \cdot (13.2mg/L - 0.4mg/L)}{\frac{1.36mg/L}{2mg/L}}) - 2.5mg/d}{1.42 \cdot 1200mg/L}

Next Step Convert Units

∴

Q w' = \frac{(\frac{10m³/s \cdot (0.0132kg/m³ - 0.0004kg/m³)}{\frac{0.0014kg/m³}{0.002kg/m³}}) - 2.9E-11kg/s}{1.42 \cdot 1.2kg/m³}

Next Step Prepare to Evaluate

∴

Q w' = \frac{(\frac{10 \cdot (0.0132 - 0.0004)}{\frac{0.0014}{0.002}}) - 2.9E-11}{1.42 \cdot 1.2}

Next Step Evaluate

∴

Q w' = 0.110466721883047m³/s

LAST Step Rounding Answer

∴

Q w' = 0.1105m³/s

Volume of Wasted Sludge Per Day given Ultimate BOD Formula Elements

Variables

Volume of Wasted Sludge

Volume of Wasted Sludge is the amount of sludge that is removed or wasted from a wastewater treatment process on a daily basis.

Symbol: Q_w'

Measurement: Volumetric Flow RateUnit: m³/s

Note: Value should be greater than 0.

Sewage Discharge

Sewage Discharge is the flow rate of sewage when it is being discharged in the river.

Symbol: Q_s

Measurement: Volumetric Flow RateUnit: m³/s

Note: Value should be greater than 0.

Influent BOD

Influent BOD is the total amount of BOD which is present in the incoming sewage.

Symbol: Q_i

Measurement: DensityUnit: mg/L

Note: Value should be greater than 0.

Effluent BOD

Effluent BOD is the amount of BOD present in the outing sewage.

Symbol: Q

Measurement: DensityUnit: mg/L

Note: Value should be greater than 0.

5 Days BOD

5 Days BOD is an indicator of how much oxygen is utilized by a natural water sample in five days at 20 degrees C.

Symbol: BOD5

Measurement: DensityUnit: mg/L

Note: Value should be greater than 0.

Ultimate BOD

Ultimate BOD is the amount of oxygen required to decompose all of the organic material after infinite time.

Symbol: BOD^u

Measurement: DensityUnit: mg/L

Note: Value should be greater than 0.

Theoretical Oxygen Requirement

Theoretical Oxygen Requirement is the calculated amount of oxygen required to oxidize a compound to its final oxidation products.

Symbol: O₂

Measurement: Mass Flow RateUnit: mg/d

Note: Value should be greater than 0.

MLSS

MLSS is the sum of volatile suspended solids (organics) and fixed suspended solids (inorganics).

Symbol: X

Measurement: DensityUnit: mg/L

Note: Value should be between 1000 to 6500.

Credits

Creator Image

Created by Suraj Kumar

Birsa Institute of Technology (BIT), Sindri

Suraj Kumar has created this Formula and 2100+ more formulas!

Verifier Image

Verified by Ishita Goyal

Meerut Institute of Engineering and Technology (MIET), Meerut

Ishita Goyal has verified this Formula and 2600+ more formulas!

Other Formulas to find Volume of Wasted Sludge

Go Volume of Wasted Sludge Per Day given Oxygen Required in Aeration Tank

Q w' = \frac{(\frac{Q s \cdot (Q i - Q)}{f}) - O 2}{1.42 \cdot X}

Go Volume of Wasted Sludge Per Day given Oxygen Demand of Biomass

Q w' = \frac{(\frac{Q s \cdot (Q i - Q)}{f}) - O 2}{D O2 \cdot X}

How to Evaluate Volume of Wasted Sludge Per Day given Ultimate BOD?

Volume of Wasted Sludge Per Day given Ultimate BOD evaluator uses Volume of Wasted Sludge = (((Sewage Discharge*(Influent BOD-Effluent BOD))/(5 Days BOD/Ultimate BOD))-Theoretical Oxygen Requirement)/(1.42*MLSS) to evaluate the Volume of Wasted Sludge, The Volume of Wasted Sludge Per Day given Ultimate BOD formula is defined as the calculation of volume of wasted sludge when we have prior information of ultimate BOD. Volume of Wasted Sludge is denoted by Q_w' symbol.

How to evaluate Volume of Wasted Sludge Per Day given Ultimate BOD using this online evaluator? To use this online evaluator for Volume of Wasted Sludge Per Day given Ultimate BOD, enter Sewage Discharge (Q_s), Influent BOD (Q_i), Effluent BOD (Q), 5 Days BOD (BOD5), Ultimate BOD (BOD^u), Theoretical Oxygen Requirement (O₂) & MLSS (X) and hit the calculate button.

FAQs on Volume of Wasted Sludge Per Day given Ultimate BOD

What is the formula to find Volume of Wasted Sludge Per Day given Ultimate BOD?

The formula of Volume of Wasted Sludge Per Day given Ultimate BOD is expressed as Volume of Wasted Sludge = (((Sewage Discharge*(Influent BOD-Effluent BOD))/(5 Days BOD/Ultimate BOD))-Theoretical Oxygen Requirement)/(1.42*MLSS). Here is an example- 0.110467 = (((10*(0.0132-0.0004))/(0.00136/0.002))-2.89351851851852E-11)/(1.42*1.2).

How to calculate Volume of Wasted Sludge Per Day given Ultimate BOD?

With Sewage Discharge (Q_s), Influent BOD (Q_i), Effluent BOD (Q), 5 Days BOD (BOD5), Ultimate BOD (BOD^u), Theoretical Oxygen Requirement (O₂) & MLSS (X) we can find Volume of Wasted Sludge Per Day given Ultimate BOD using the formula - Volume of Wasted Sludge = (((Sewage Discharge*(Influent BOD-Effluent BOD))/(5 Days BOD/Ultimate BOD))-Theoretical Oxygen Requirement)/(1.42*MLSS).

What are the other ways to Calculate Volume of Wasted Sludge?

Here are the different ways to Calculate Volume of Wasted Sludge-

Volume of Wasted Sludge=(((Sewage Discharge*(Influent BOD-Effluent BOD))/Ratio of BOD to Ultimate BOD)-Theoretical Oxygen Requirement)/(1.42*MLSS)
Volume of Wasted Sludge=(((Sewage Discharge*(Influent BOD-Effluent BOD))/Ratio of BOD to Ultimate BOD)-Theoretical Oxygen Requirement)/(Oxygen Demand of Biomass*MLSS)
Volume of Wasted Sludge=(((Sewage Discharge*(Influent BOD-Effluent BOD))/(5 Days BOD/Ultimate BOD))-Theoretical Oxygen Requirement)/(Oxygen Demand of Biomass*MLSS)

Can the Volume of Wasted Sludge Per Day given Ultimate BOD be negative?

No, the Volume of Wasted Sludge Per Day given Ultimate BOD, measured in Volumetric Flow Rate cannot be negative.

Which unit is used to measure Volume of Wasted Sludge Per Day given Ultimate BOD?

Volume of Wasted Sludge Per Day given Ultimate BOD is usually measured using the Cubic Meter per Second[m³/s] for Volumetric Flow Rate. Cubic Meter per Day[m³/s], Cubic Meter per Hour[m³/s], Cubic Meter per Minute[m³/s] are the few other units in which Volume of Wasted Sludge Per Day given Ultimate BOD can be measured.

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