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Tan (A-B)/2 is the value of the trigonometric tangent function of angle A minus angle B whole by 2 of the triangle. Check FAQs
tan(A-B)/2=(sin(A-B)/2sin(A+B)/2)tan(C/2)
tan(A-B)/2 - Tan (A-B)/2?sin(A-B)/2 - Sin (A-B)/2?sin(A+B)/2 - Sin (A+B)/2?tan(C/2) - Tan (C/2)?

Tan (A-B)/2 given Sin (A+B)/2 , Sin (A-B)/2 and Tan C/2 Example

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Here is how the Tan (A-B)/2 given Sin (A+B)/2 , Sin (A-B)/2 and Tan C/2 equation looks like with Values.

Here is how the Tan (A-B)/2 given Sin (A+B)/2 , Sin (A-B)/2 and Tan C/2 equation looks like with Units.

Here is how the Tan (A-B)/2 given Sin (A+B)/2 , Sin (A-B)/2 and Tan C/2 equation looks like.

-0.1907Edit=(-0.08Edit0.6Edit)1.43Edit
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Tan (A-B)/2 given Sin (A+B)/2 , Sin (A-B)/2 and Tan C/2 Solution

Follow our step by step solution on how to calculate Tan (A-B)/2 given Sin (A+B)/2 , Sin (A-B)/2 and Tan C/2?

FIRST Step Consider the formula
tan(A-B)/2=(sin(A-B)/2sin(A+B)/2)tan(C/2)
Next Step Substitute values of Variables
tan(A-B)/2=(-0.080.6)1.43
Next Step Prepare to Evaluate
tan(A-B)/2=(-0.080.6)1.43
Next Step Evaluate
tan(A-B)/2=-0.190666666666667
LAST Step Rounding Answer
tan(A-B)/2=-0.1907

Tan (A-B)/2 given Sin (A+B)/2 , Sin (A-B)/2 and Tan C/2 Formula Elements

Variables
Tan (A-B)/2
Tan (A-B)/2 is the value of the trigonometric tangent function of angle A minus angle B whole by 2 of the triangle.
Symbol: tan(A-B)/2
Measurement: NAUnit: Unitless
Note: Value can be positive or negative.
Sin (A-B)/2
Sin (A-B)/2 is the value of the trigonometric sine function of angle A minus angle B whole by 2 of the triangle.
Symbol: sin(A-B)/2
Measurement: NAUnit: Unitless
Note: Value should be between -1.01 to 1.01.
Sin (A+B)/2
Sin (A+B)/2 is the value of the trigonometric sine function of angle A plus angle B whole by 2 of the triangle.
Symbol: sin(A+B)/2
Measurement: NAUnit: Unitless
Note: Value should be between -1.01 to 1.01.
Tan (C/2)
Tan (C/2) is the value of the trigonometric tangent function of half of the given angle B.
Symbol: tan(C/2)
Measurement: NAUnit: Unitless
Note: Value can be positive or negative.

Credits

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Created by Surjojoti Som LinkedIn Logo
Rashtreeya Vidyalaya College of Engineering (RVCE), Bangalore
Surjojoti Som has created this Formula and 200+ more formulas!
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Verified by Nayana Phulphagar LinkedIn Logo
Institute of Chartered and Financial Analysts of India National college (ICFAI National College), HUBLI
Nayana Phulphagar has verified this Formula and 1500+ more formulas!

Other Formulas to find Tan (A-B)/2

​Go Tan (A-B)/2 given Cot C/2
tan(A-B)/2=(Sa-SbSa+Sb)cot(C/2)
​Go Tan (A-B)/2 given Sin (A+B)/2 , Sin (A-B)/2 and Cot C/2
tan(A-B)/2=(sin(A-B)/2sin(A+B)/2)cot(C/2)

Other formulas in Tangent Rule or Napier's Analogy category

​Go Tan (C-A)/2 given Cot B/2
tan(C-A)/2=(Sc-SaSc+Sa)cot(B/2)
​Go Tan (B-C)/2 given Cot A/2
tan(B-C)/2=(Sb-ScSb+Sc)cot(A/2)
​Go Tan (A+B)/2 given Cos (A+B)/2 , Cos (A-B)/2 and Tan C/2
tan(A+B)/2=(cos(A-B)/2cos(A+B)/2)tan(C/2)
​Go Tan (A+B)/2 given Cos (A+B)/2 , Cos (A-B)/2 and Cot C/2
tan(A+B)/2=(cos(A-B)/2cos(A+B)/2)cot(C/2)

How to Evaluate Tan (A-B)/2 given Sin (A+B)/2 , Sin (A-B)/2 and Tan C/2?

Tan (A-B)/2 given Sin (A+B)/2 , Sin (A-B)/2 and Tan C/2 evaluator uses Tan (A-B)/2 = (Sin (A-B)/2/Sin (A+B)/2)*Tan (C/2) to evaluate the Tan (A-B)/2, The Tan (A-B)/2 given Sin (A+B)/2 , Sin (A-B)/2 and Tan C/2 formula is defined as the value of Tan (A-B)/2 using the values of the Sin (A+B)/2, Sin (A-B)/2 and Tan C/2 of the triangle. Tan (A-B)/2 is denoted by tan(A-B)/2 symbol.

How to evaluate Tan (A-B)/2 given Sin (A+B)/2 , Sin (A-B)/2 and Tan C/2 using this online evaluator? To use this online evaluator for Tan (A-B)/2 given Sin (A+B)/2 , Sin (A-B)/2 and Tan C/2, enter Sin (A-B)/2 (sin(A-B)/2), Sin (A+B)/2 (sin(A+B)/2) & Tan (C/2) (tan(C/2)) and hit the calculate button.

FAQs on Tan (A-B)/2 given Sin (A+B)/2 , Sin (A-B)/2 and Tan C/2

What is the formula to find Tan (A-B)/2 given Sin (A+B)/2 , Sin (A-B)/2 and Tan C/2?
The formula of Tan (A-B)/2 given Sin (A+B)/2 , Sin (A-B)/2 and Tan C/2 is expressed as Tan (A-B)/2 = (Sin (A-B)/2/Sin (A+B)/2)*Tan (C/2). Here is an example- -0.186667 = ((-0.08)/0.6)*1.43.
How to calculate Tan (A-B)/2 given Sin (A+B)/2 , Sin (A-B)/2 and Tan C/2?
With Sin (A-B)/2 (sin(A-B)/2), Sin (A+B)/2 (sin(A+B)/2) & Tan (C/2) (tan(C/2)) we can find Tan (A-B)/2 given Sin (A+B)/2 , Sin (A-B)/2 and Tan C/2 using the formula - Tan (A-B)/2 = (Sin (A-B)/2/Sin (A+B)/2)*Tan (C/2).
What are the other ways to Calculate Tan (A-B)/2?
Here are the different ways to Calculate Tan (A-B)/2-
  • Tan (A-B)/2=((Side A of Triangle-Side B of Triangle)/(Side A of Triangle+Side B of Triangle))*Cot C/2OpenImg
  • Tan (A-B)/2=(Sin (A-B)/2/Sin (A+B)/2)*Cot C/2OpenImg
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