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Shear stress in crankpin of centre crankshaft for max torque Formula

GoShear stress in crankpin of centre crankshaft for max torque given bending and torsional moment Formula

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Shear stress in central plane of crank pin is the amount of shear stress (causes deformation by slippage along plane parallel to the imposed stress) at the central plane of the crank pin. Check FAQs

τ = (\frac{16}{π \cdot {d c}^{3}}) \cdot \sqrt{{(R v1 \cdot b 1)}^{2} + {(R h1 \cdot r)}^{2}}

τ - Shear Stress in Central Plane of Crank Pin?d_c - Diameter of Crank Pin?R_v1 - Vertical Reaction at Bearing 1 due to Radial Force?b₁ - Centre Crankshaft Bearing1 Gap from CrankPinCentre?R_h1 - Horizontal Force at Bearing1 by Tangential Force?r - Distance Between Crankpin and Crankshaft?π - Archimedes' constant?

Shear stress in crankpin of centre crankshaft for max torque Example

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Here is how the Shear stress in crankpin of centre crankshaft for max torque equation looks like with Values.

Here is how the Shear stress in crankpin of centre crankshaft for max torque equation looks like with Units.

Here is how the Shear stress in crankpin of centre crankshaft for max torque equation looks like.

19.9769 = (\frac{16}{3.1416 \cdot 50^{3}}) \cdot \sqrt{{(1000 \cdot 100.01)}^{2} + {(6000 \cdot 80)}^{2}}

19.9769N/mm² = (\frac{16}{3.1416 \cdot {50mm}^{3}}) \cdot \sqrt{{(1000N \cdot 100.01mm)}^{2} + {(6000N \cdot 80mm)}^{2}}

19.9769 = (\frac{16}{3.1416 \cdot 50^{3}}) \cdot \sqrt{{(1000 \cdot 100.01)}^{2} + {(6000 \cdot 80)}^{2}}

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Shear stress in crankpin of centre crankshaft for max torque Solution

Follow our step by step solution on how to calculate Shear stress in crankpin of centre crankshaft for max torque?

FIRST Step Consider the formula

τ = (\frac{16}{π \cdot {d c}^{3}}) \cdot \sqrt{{(R v1 \cdot b 1)}^{2} + {(R h1 \cdot r)}^{2}}

Next Step Substitute values of Variables

∴

τ = (\frac{16}{π \cdot {50mm}^{3}}) \cdot \sqrt{{(1000N \cdot 100.01mm)}^{2} + {(6000N \cdot 80mm)}^{2}}

Next Step Substitute values of Constants

∴

τ = (\frac{16}{3.1416 \cdot {50mm}^{3}}) \cdot \sqrt{{(1000N \cdot 100.01mm)}^{2} + {(6000N \cdot 80mm)}^{2}}

Next Step Convert Units

∴

τ = (\frac{16}{3.1416 \cdot {0.05m}^{3}}) \cdot \sqrt{{(1000N \cdot 0.1m)}^{2} + {(6000N \cdot 0.08m)}^{2}}

Next Step Prepare to Evaluate

∴

τ = (\frac{16}{3.1416 \cdot {0.05}^{3}}) \cdot \sqrt{{(1000 \cdot 0.1)}^{2} + {(6000 \cdot 0.08)}^{2}}

Next Step Evaluate

∴

τ = 19976947.820894Pa

Next Step Convert to Output's Unit

∴

τ = 19.976947820894N/mm²

LAST Step Rounding Answer

∴

τ = 19.9769N/mm²

Shear stress in crankpin of centre crankshaft for max torque Formula Elements

Variables

Constants

Functions

Shear Stress in Central Plane of Crank Pin

Shear stress in central plane of crank pin is the amount of shear stress (causes deformation by slippage along plane parallel to the imposed stress) at the central plane of the crank pin.

Symbol: τ

Measurement: StressUnit: N/mm²