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Ratio of Molecular Mass of 2 Immiscible Liquids Formula

GoRatio of Molecular Masses of Water to Liquid forming Immiscible Mixture Formula

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The Ratio of Molecular Masses of 2 immiscible liquids in a mixture say liquid A and liquid B. Check FAQs

M A:B = \frac{P B ° \cdot W A}{P A ° \cdot W B}

M_A:B - Ratio of Molecular Masses of 2 Immiscible Liquids?P_B° - Vapor Pressure of Pure Component B?W_A - Weight of Liquid A?P_A° - Vapor Pressure of Pure Component A?W_B - Weight of Liquid B?

Ratio of Molecular Mass of 2 Immiscible Liquids Example

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Here is how the Ratio of Molecular Mass of 2 Immiscible Liquids equation looks like with Values.

Here is how the Ratio of Molecular Mass of 2 Immiscible Liquids equation looks like with Units.

Here is how the Ratio of Molecular Mass of 2 Immiscible Liquids equation looks like.

0.463 = \frac{0.25 \cdot 0.5}{2.7 \cdot 0.1}

0.463 = \frac{0.25Pa \cdot 0.5g}{2.7Pa \cdot 0.1g}

0.463 = \frac{0.25 \cdot 0.5}{2.7 \cdot 0.1}

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Immiscible Liquids » fx Ratio of Molecular Mass of 2 Immiscible Liquids

Ratio of Molecular Mass of 2 Immiscible Liquids Solution

Follow our step by step solution on how to calculate Ratio of Molecular Mass of 2 Immiscible Liquids?

FIRST Step Consider the formula

M A:B = \frac{P B ° \cdot W A}{P A ° \cdot W B}

Next Step Substitute values of Variables

∴

M A:B = \frac{0.25Pa \cdot 0.5g}{2.7Pa \cdot 0.1g}

Next Step Convert Units

∴

M A:B = \frac{0.25Pa \cdot 0.0005kg}{2.7Pa \cdot 0.0001kg}

Next Step Prepare to Evaluate

∴

M A:B = \frac{0.25 \cdot 0.0005}{2.7 \cdot 0.0001}

Next Step Evaluate

∴

M A:B = 0.462962962962963

LAST Step Rounding Answer

∴

M A:B = 0.463

Ratio of Molecular Mass of 2 Immiscible Liquids Formula Elements

Variables

Ratio of Molecular Masses of 2 Immiscible Liquids

The Ratio of Molecular Masses of 2 immiscible liquids in a mixture say liquid A and liquid B.

Symbol: M_A:B

Measurement: NAUnit: Unitless

Note: Value should be greater than 0.

Formulas to find Ratio of Molecular Masses of 2 Immiscible Liquids

Vapor Pressure of Pure Component B

Vapor Pressure of Pure Component B is the pressure exerted by a liquid or solid molecules of only B in a closed system in which they are in equilibrium with the vapour phase.

Symbol: P_B°

Measurement: PressureUnit: Pa

Note: Value can be positive or negative.

Formulas to find Vapor Pressure of Pure Component B

Weight of Liquid A

The Weight of Liquid A in a mixture of immiscible liquids.

Symbol: W_A

Measurement: WeightUnit: g

Note: Value should be greater than 0.

Formulas to find Weight of Liquid A

Vapor Pressure of Pure Component A

Vapor Pressure of Pure Component A is the pressure exerted by a liquid or solid molecules of only A in a closed system in which they are in equilibrium with the vapour phase.

Symbol: P_A°

Measurement: PressureUnit: Pa

Note: Value can be positive or negative.

Formulas to find Vapor Pressure of Pure Component A

Weight of Liquid B

The Weight of Liquid B in a mixture of immiscible liquids.

Symbol: W_B

Measurement: WeightUnit: g

Note: Value should be greater than 0.

Formulas to find Weight of Liquid B

Credits

Created by Prerana Bakli

University of Hawaiʻi at Mānoa (UH Manoa), Hawaii, USA

Prerana Bakli has created this Formula and 800+ more formulas!

Verified by Akshada Kulkarni

National Institute of Information Technology (NIIT), Neemrana

Akshada Kulkarni has verified this Formula and 900+ more formulas!

Other Formulas to find Ratio of Molecular Masses of 2 Immiscible Liquids

Go Ratio of Molecular Masses of Water to Liquid forming Immiscible Mixture

M A:B = \frac{W water \cdot P B °}{P o water \cdot W B}

Other formulas in Immiscible Liquids category

Go Total Pressure of Mixture of Two Immiscible Liquids

P = P A ° + P B °

Go Partial Vapour Pressure of Immiscible Liquid given Partial Pressure of other Liquid

P A ° = \frac{W A \cdot M B \cdot P B °}{M A \cdot W B}

Go Ratio of Partial Vapour Pressures of 2 Immiscible Liquids given Weight and Molecular Mass

P A:B = \frac{W A \cdot M B}{W B \cdot M A}

Go Ratio of Partial Pressure of 2 Immiscible Liquids given Number of Moles

P A:B = \frac{n A}{n B}

How to Evaluate Ratio of Molecular Mass of 2 Immiscible Liquids?

Ratio of Molecular Mass of 2 Immiscible Liquids evaluator uses Ratio of Molecular Masses of 2 Immiscible Liquids = (Vapor Pressure of Pure Component B*Weight of Liquid A)/(Vapor Pressure of Pure Component A*Weight of Liquid B) to evaluate the Ratio of Molecular Masses of 2 Immiscible Liquids, The Ratio of Molecular Mass of 2 Immiscible Liquids formula is defined as the ratio of the molecular masses in mixture. Ratio of Molecular Masses of 2 Immiscible Liquids is denoted by M_A:B symbol.

How to evaluate Ratio of Molecular Mass of 2 Immiscible Liquids using this online evaluator? To use this online evaluator for Ratio of Molecular Mass of 2 Immiscible Liquids, enter Vapor Pressure of Pure Component B (P_B°), Weight of Liquid A (W_A), Vapor Pressure of Pure Component A (P_A°) & Weight of Liquid B (W_B) and hit the calculate button.

FAQs on Ratio of Molecular Mass of 2 Immiscible Liquids

What is the formula to find Ratio of Molecular Mass of 2 Immiscible Liquids?

The formula of Ratio of Molecular Mass of 2 Immiscible Liquids is expressed as Ratio of Molecular Masses of 2 Immiscible Liquids = (Vapor Pressure of Pure Component B*Weight of Liquid A)/(Vapor Pressure of Pure Component A*Weight of Liquid B). Here is an example- 0.462963 = (0.25*0.0005)/(2.7*0.0001).

How to calculate Ratio of Molecular Mass of 2 Immiscible Liquids?

With Vapor Pressure of Pure Component B (P_B°), Weight of Liquid A (W_A), Vapor Pressure of Pure Component A (P_A°) & Weight of Liquid B (W_B) we can find Ratio of Molecular Mass of 2 Immiscible Liquids using the formula - Ratio of Molecular Masses of 2 Immiscible Liquids = (Vapor Pressure of Pure Component B*Weight of Liquid A)/(Vapor Pressure of Pure Component A*Weight of Liquid B).

What are the other ways to Calculate Ratio of Molecular Masses of 2 Immiscible Liquids?

Here are the different ways to Calculate Ratio of Molecular Masses of 2 Immiscible Liquids-

Ratio of Molecular Masses of 2 Immiscible Liquids=(Weight of Water in Immiscible Mixture*Vapor Pressure of Pure Component B)/(Partial Pressure of Pure Water*Weight of Liquid B)