Moon's Tide-generating Attractive Force Potential Formula

GoAttractive Force Potentials per unit Mass for Moon Formula

GoAttractive Force Potentials per unit Mass for Moon given Harmonic Polynomial Expansion Formula

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Attractive Force Potentials for Moon refers to the gravitational force exerted by the Moon on other objects, such as the Earth or objects on the Earth's surface. Check FAQs

V M = f \cdot M \cdot ((\frac{1}{r S/MX}) - (\frac{1}{r m}) - ([Earth-R] \cdot \frac{\cos (θ m/s)}{{r m}^{2}}))

V_M - Attractive Force Potentials for Moon?f - Universal Constant?M - Mass of the Moon?r_S/MX - Distance of Point?r_m - Distance from center of Earth to center of Moon?θ_m/s - Angle made by the Distance of Point?[Earth-R] - Earth mean radius?

Moon's Tide-generating Attractive Force Potential Example

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Here is how the Moon's Tide-generating Attractive Force Potential equation looks like with Values.

Here is how the Moon's Tide-generating Attractive Force Potential equation looks like with Units.

Here is how the Moon's Tide-generating Attractive Force Potential equation looks like.

5.7E+17 = 2 \cdot 7.4E+22 \cdot ((\frac{1}{256}) - (\frac{1}{384467}) - (6371.0088 \cdot \frac{\cos (12.5)}{384467^{2}}))

5.7E+17 = 2 \cdot 7.4E+22kg \cdot ((\frac{1}{256km}) - (\frac{1}{384467km}) - (6371.0088km \cdot \frac{\cos (12.5°)}{{384467km}^{2}}))

5.7E+17 = 2 \cdot 7.4E+22 \cdot ((\frac{1}{256}) - (\frac{1}{384467}) - (6371.0088 \cdot \frac{\cos (12.5)}{384467^{2}}))

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Moon's Tide-generating Attractive Force Potential Solution

Follow our step by step solution on how to calculate Moon's Tide-generating Attractive Force Potential?

FIRST Step Consider the formula

V M = f \cdot M \cdot ((\frac{1}{r S/MX}) - (\frac{1}{r m}) - ([Earth-R] \cdot \frac{\cos (θ m/s)}{{r m}^{2}}))

Next Step Substitute values of Variables

∴

V M = 2 \cdot 7.4E+22kg \cdot ((\frac{1}{256km}) - (\frac{1}{384467km}) - ([Earth-R] \cdot \frac{\cos (12.5°)}{{384467km}^{2}}))

Next Step Substitute values of Constants

∴

V M = 2 \cdot 7.4E+22kg \cdot ((\frac{1}{256km}) - (\frac{1}{384467km}) - (6371.0088km \cdot \frac{\cos (12.5°)}{{384467km}^{2}}))

Next Step Convert Units

∴

V M = 2 \cdot 7.4E+22kg \cdot ((\frac{1}{256000m}) - (\frac{1}{3.8E+8m}) - (6371.0088km \cdot \frac{\cos (0.2182rad)}{{3.8E+8m}^{2}}))

Next Step Prepare to Evaluate

∴

V M = 2 \cdot 7.4E+22 \cdot ((\frac{1}{256000}) - (\frac{1}{3.8E+8}) - (6371.0088 \cdot \frac{\cos (0.2182)}{{3.8E+8}^{2}}))

Next Step Evaluate

∴

V M = 5.73830216789452E+17

LAST Step Rounding Answer

∴

V M = 5.7E+17

Moon's Tide-generating Attractive Force Potential Formula Elements

Variables

Constants

Functions

Attractive Force Potentials for Moon

Attractive Force Potentials for Moon refers to the gravitational force exerted by the Moon on other objects, such as the Earth or objects on the Earth's surface.

Symbol: V_M

Measurement: NAUnit: Unitless