Modulus of Elasticity given Deflection at Section of Column with Eccentric Load Formula

GoModulus of Elasticity given Deflection at Free End of Column with Eccentric Load Formula

GoModulus of Elasticity given Maximum Stress for Column with Eccentric Load Formula

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Modulus of elasticity of column is a measure of a material’s stiffness or rigidity, is defined as the ratio of longitudinal stress to longitudinal strain within the elastic limit of a material. Check FAQs

ε column = (\frac{P}{I \cdot ({(\frac{a \cos (1 - (\frac{δ c}{δ + e load}))}{x})}^{2})})

ε_column - Modulus of Elasticity of Column?P - Eccentric Load on Column?I - Moment of Inertia?δ_c - Deflection of Column?δ - Deflection of Free End?e_load - Eccentricity of Load?x - Distance b/w Fixed End and Deflection Point?

Modulus of Elasticity given Deflection at Section of Column with Eccentric Load Example

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Here is how the Modulus of Elasticity given Deflection at Section of Column with Eccentric Load equation looks like with Values.

Here is how the Modulus of Elasticity given Deflection at Section of Column with Eccentric Load equation looks like with Units.

Here is how the Modulus of Elasticity given Deflection at Section of Column with Eccentric Load equation looks like.

2 = (\frac{40}{0.0002 \cdot ({(\frac{a \cos (1 - (\frac{12}{201.112 + 2.5}))}{1000})}^{2})})

2MPa = (\frac{40N}{0.0002kg·m² \cdot ({(\frac{a \cos (1 - (\frac{12mm}{201.112mm + 2.5mm}))}{1000mm})}^{2})})

2 = (\frac{40}{0.0002 \cdot ({(\frac{a \cos (1 - (\frac{12}{201.112 + 2.5}))}{1000})}^{2})})

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Home » Physics » Mechanical » Strength of Materials » Modulus of Elasticity given Deflection at Section of Column with Eccentric Load

Modulus of Elasticity given Deflection at Section of Column with Eccentric Load Solution

Follow our step by step solution on how to calculate Modulus of Elasticity given Deflection at Section of Column with Eccentric Load?

FIRST Step Consider the formula

ε column = (\frac{P}{I \cdot ({(\frac{a \cos (1 - (\frac{δ c}{δ + e load}))}{x})}^{2})})

Next Step Substitute values of Variables

∴

ε column = (\frac{40N}{0.0002kg·m² \cdot ({(\frac{a \cos (1 - (\frac{12mm}{201.112mm + 2.5mm}))}{1000mm})}^{2})})

Next Step Convert Units

∴

ε column = (\frac{40N}{0.0002kg·m² \cdot ({(\frac{a \cos (1 - (\frac{0.012m}{0.2011m + 0.0025m}))}{1m})}^{2})})

Next Step Prepare to Evaluate

∴

ε column = (\frac{40}{0.0002 \cdot ({(\frac{a \cos (1 - (\frac{0.012}{0.2011 + 0.0025}))}{1})}^{2})})

Next Step Evaluate

∴

ε column = 2000000.38458075Pa

Next Step Convert to Output's Unit

∴

ε column = 2.00000038458075MPa

LAST Step Rounding Answer

∴

ε column = 2MPa

Modulus of Elasticity given Deflection at Section of Column with Eccentric Load Formula Elements

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Modulus of Elasticity of Column

Modulus of elasticity of column is a measure of a material’s stiffness or rigidity, is defined as the ratio of longitudinal stress to longitudinal strain within the elastic limit of a material.

Symbol: ε_column

Measurement: PressureUnit: MPa