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Frictional Force given Minor diameter of bolt Formula

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Friction force in metallic gasket is the force arising in the metallic gasket due to the friction between the surfaces. Check FAQs

F μ = \frac{(d 2 - (\frac{\sqrt{({(d 1)}^{2} - {(d gb)}^{2}) \cdot p s}}{\sqrt{(i \cdot F c)}})) \cdot 3.14 \cdot i \cdot F c}{4}

F_μ - Friction Force in Metallic Gasket?d₂ - Minor Diameter of Metallic Gasket Bolt?d₁ - Outside Diameter of Seal Ring?d_gb - Nominal Diameter of Metallic Gasket Bolt?p_s - Fluid Pressure on Metallic Gasket Seal?i - Number of Bolts in Metallic Gasket Seal?F_c - Design Stress for Metallic Gasket?

Frictional Force given Minor diameter of bolt Example

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Here is how the Frictional Force given Minor diameter of bolt equation looks like with Values.

Here is how the Frictional Force given Minor diameter of bolt equation looks like with Units.

Here is how the Frictional Force given Minor diameter of bolt equation looks like.

500.196 = \frac{(832 - (\frac{\sqrt{({(6)}^{2} - {(4)}^{2}) \cdot 4.25}}{\sqrt{(2 \cdot 0.0006)}})) \cdot 3.14 \cdot 2 \cdot 0.0006}{4}

500.196N = \frac{(832mm - (\frac{\sqrt{({(6mm)}^{2} - {(4mm)}^{2}) \cdot 4.25MPa}}{\sqrt{(2 \cdot 0.0006N/mm²)}})) \cdot 3.14 \cdot 2 \cdot 0.0006N/mm²}{4}

500.196 = \frac{(832 - (\frac{\sqrt{({(6)}^{2} - {(4)}^{2}) \cdot 4.25}}{\sqrt{(2 \cdot 0.0006)}})) \cdot 3.14 \cdot 2 \cdot 0.0006}{4}

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Home » Physics » Mechanical » Design of Machine Elements » Frictional Force given Minor diameter of bolt

Frictional Force given Minor diameter of bolt Solution

Follow our step by step solution on how to calculate Frictional Force given Minor diameter of bolt?

FIRST Step Consider the formula

F μ = \frac{(d 2 - (\frac{\sqrt{({(d 1)}^{2} - {(d gb)}^{2}) \cdot p s}}{\sqrt{(i \cdot F c)}})) \cdot 3.14 \cdot i \cdot F c}{4}

Next Step Substitute values of Variables

∴

F μ = \frac{(832mm - (\frac{\sqrt{({(6mm)}^{2} - {(4mm)}^{2}) \cdot 4.25MPa}}{\sqrt{(2 \cdot 0.0006N/mm²)}})) \cdot 3.14 \cdot 2 \cdot 0.0006N/mm²}{4}

Next Step Convert Units

∴

F μ = \frac{(0.832m - (\frac{\sqrt{({(0.006m)}^{2} - {(0.004m)}^{2}) \cdot 4.3E+6Pa}}{\sqrt{(2 \cdot 570Pa)}})) \cdot 3.14 \cdot 2 \cdot 570Pa}{4}

Next Step Prepare to Evaluate

∴

F μ = \frac{(0.832 - (\frac{\sqrt{({(0.006)}^{2} - {(0.004)}^{2}) \cdot 4.3E+6}}{\sqrt{(2 \cdot 570)}})) \cdot 3.14 \cdot 2 \cdot 570}{4}

Next Step Evaluate

∴

F μ = 500.195996064508N

LAST Step Rounding Answer

∴

F μ = 500.196N

Frictional Force given Minor diameter of bolt Formula Elements

Variables

Functions

Friction Force in Metallic Gasket

Friction force in metallic gasket is the force arising in the metallic gasket due to the friction between the surfaces.

Symbol: F_μ

Measurement: ForceUnit: N

Note: Value should be greater than 0.

Minor Diameter of Metallic Gasket Bolt

The Minor Diameter of Metallic Gasket Bolt is the core diameter of the bolt used in with the metallic gasket.

Symbol: d₂

Measurement: LengthUnit: mm

Note: Value should be greater than 0.

Outside Diameter of Seal Ring

The Outside Diameter of Seal Ring is any straight line segment that passes through the center of the ring and whose endpoints lie on the ring.

Symbol: d₁

Measurement: LengthUnit: mm

Note: Value should be greater than 0.

Nominal Diameter of Metallic Gasket Bolt

Nominal diameter of metallic gasket bolt is the major diameter of the bolt used in with the metallic gasket.

Symbol: d_gb

Measurement: LengthUnit: mm

Note: Value should be greater than 0.

Fluid Pressure on Metallic Gasket Seal

The Fluid Pressure on Metallic Gasket Seal refers to the pressure exerted by the fluid onto the metallic gasket seal.

Symbol: p_s

Measurement: PressureUnit: MPa

Note: Value should be greater than 0.

Number of Bolts in Metallic Gasket Seal

Number of bolts in metallic gasket seal is simply defined as the number of bolts that are under our consideration.

Symbol: i

Measurement: NAUnit: Unitless

Note: Value should be greater than 0.

Design Stress for Metallic Gasket

Design Stress for metallic gasket is the stress for which the metallic gasket is designed.

Symbol: F_c

Measurement: StressUnit: N/mm²

Note: Value should be greater than 0.

sqrt

A square root function is a function that takes a non-negative number as an input and returns the square root of the given input number.

Syntax: sqrt(Number)

Credits

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Created by

national institute of technology hamirpur (NITH ), Hamirpur, Himachal Pradesh

sanjay shiva has created this Formula and 100+ more formulas!

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Verified by Anshika Arya

National Institute Of Technology (NIT), Hamirpur

Anshika Arya has verified this Formula and 2500+ more formulas!

Other formulas in Metallic Gaskets category

Go Minor Diameter of Bolt given Working Strength

d 2 = (\frac{\sqrt{({(d 1)}^{2} - {(d gb)}^{2}) \cdot p s}}{\sqrt{(i \cdot 68.7)}}) + \frac{4 \cdot F μ}{3.14 \cdot i \cdot 68.7}

How to Evaluate Frictional Force given Minor diameter of bolt?

Frictional Force given Minor diameter of bolt evaluator uses Friction Force in Metallic Gasket = ((Minor Diameter of Metallic Gasket Bolt-(sqrt(((Outside Diameter of Seal Ring)^2-(Nominal Diameter of Metallic Gasket Bolt)^2)*Fluid Pressure on Metallic Gasket Seal)/sqrt((Number of Bolts in Metallic Gasket Seal*Design Stress for Metallic Gasket))))*3.14*Number of Bolts in Metallic Gasket Seal*Design Stress for Metallic Gasket)/4 to evaluate the Friction Force in Metallic Gasket, The Frictional Force given Minor diameter of bolt formula is defined as the force that resists motion when the surface of one object comes in contact with the surface of another. Friction Force in Metallic Gasket is denoted by F_μ symbol.

How to evaluate Frictional Force given Minor diameter of bolt using this online evaluator? To use this online evaluator for Frictional Force given Minor diameter of bolt, enter Minor Diameter of Metallic Gasket Bolt (d₂), Outside Diameter of Seal Ring (d₁), Nominal Diameter of Metallic Gasket Bolt (d_gb), Fluid Pressure on Metallic Gasket Seal (p_s), Number of Bolts in Metallic Gasket Seal (i) & Design Stress for Metallic Gasket (F_c) and hit the calculate button.

FAQs on Frictional Force given Minor diameter of bolt

What is the formula to find Frictional Force given Minor diameter of bolt?

The formula of Frictional Force given Minor diameter of bolt is expressed as Friction Force in Metallic Gasket = ((Minor Diameter of Metallic Gasket Bolt-(sqrt(((Outside Diameter of Seal Ring)^2-(Nominal Diameter of Metallic Gasket Bolt)^2)*Fluid Pressure on Metallic Gasket Seal)/sqrt((Number of Bolts in Metallic Gasket Seal*Design Stress for Metallic Gasket))))*3.14*Number of Bolts in Metallic Gasket Seal*Design Stress for Metallic Gasket)/4. Here is an example- 3.2E+7 = ((0.832-(sqrt(((0.006)^2-(0.004)^2)*4250000)/sqrt((2*570))))*3.14*2*570)/4.

How to calculate Frictional Force given Minor diameter of bolt?

With Minor Diameter of Metallic Gasket Bolt (d₂), Outside Diameter of Seal Ring (d₁), Nominal Diameter of Metallic Gasket Bolt (d_gb), Fluid Pressure on Metallic Gasket Seal (p_s), Number of Bolts in Metallic Gasket Seal (i) & Design Stress for Metallic Gasket (F_c) we can find Frictional Force given Minor diameter of bolt using the formula - Friction Force in Metallic Gasket = ((Minor Diameter of Metallic Gasket Bolt-(sqrt(((Outside Diameter of Seal Ring)^2-(Nominal Diameter of Metallic Gasket Bolt)^2)*Fluid Pressure on Metallic Gasket Seal)/sqrt((Number of Bolts in Metallic Gasket Seal*Design Stress for Metallic Gasket))))*3.14*Number of Bolts in Metallic Gasket Seal*Design Stress for Metallic Gasket)/4. This formula also uses Square Root (sqrt) function(s).

Can the Frictional Force given Minor diameter of bolt be negative?

No, the Frictional Force given Minor diameter of bolt, measured in Force cannot be negative.

Which unit is used to measure Frictional Force given Minor diameter of bolt?

Frictional Force given Minor diameter of bolt is usually measured using the Newton[N] for Force. Exanewton[N], Meganewton[N], Kilonewton[N] are the few other units in which Frictional Force given Minor diameter of bolt can be measured.

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