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C.O.P. of simple air evaporative cycle Formula

GoC.O.P. of simple air cycle Formula

GoCOP of Air Cycle for given Input Power and Tonnage of Refrigeration Formula

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Actual Coefficient of Performance is a measure of the effectiveness of an air refrigeration system in transferring heat from one location to another. Check FAQs

COP actual = \frac{210 \cdot Q}{ma \cdot C p \cdot (Tt' - T2')}

COP_actual - Actual Coefficient of Performance?Q - Tonnage of Refrigeration in TR?ma - Mass of Air?C_p - Specific Heat Capacity at Constant Pressure?Tt^' - Actual End Temp of Isentropic Compression?T2^' - Actual Temperature of Rammed Air?

C.O.P. of simple air evaporative cycle Example

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Here is how the C.O.P. of simple air evaporative cycle equation looks like with Values.

Here is how the C.O.P. of simple air evaporative cycle equation looks like with Units.

Here is how the C.O.P. of simple air evaporative cycle equation looks like.

0.2035 = \frac{210 \cdot 150}{120 \cdot 1.005 \cdot (350 - 273)}

0.2035 = \frac{210 \cdot 150}{120kg/min \cdot 1.005kJ/kg*K \cdot (350K - 273K)}

0.2035 = \frac{210 \cdot 150}{120 \cdot 1.005 \cdot (350 - 273)}

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Home » Physics » Mechanical » Refrigeration and Air Conditioning » C.O.P. of simple air evaporative cycle

C.O.P. of simple air evaporative cycle Solution

Follow our step by step solution on how to calculate C.O.P. of simple air evaporative cycle?

FIRST Step Consider the formula

COP actual = \frac{210 \cdot Q}{ma \cdot C p \cdot (Tt' - T2')}

Next Step Substitute values of Variables

∴

COP actual = \frac{210 \cdot 150}{120kg/min \cdot 1.005kJ/kg*K \cdot (350K - 273K)}

Next Step Convert Units

∴

COP actual = \frac{210 \cdot 150}{2kg/s \cdot 1005J/(kg*K) \cdot (350K - 273K)}

Next Step Prepare to Evaluate

∴

COP actual = \frac{210 \cdot 150}{2 \cdot 1005 \cdot (350 - 273)}

Next Step Evaluate

∴

COP actual = 0.203527815468114

LAST Step Rounding Answer

∴

COP actual = 0.2035

C.O.P. of simple air evaporative cycle Formula Elements

Variables

Actual Coefficient of Performance

Actual Coefficient of Performance is a measure of the effectiveness of an air refrigeration system in transferring heat from one location to another.

Symbol: COP_actual

Measurement: NAUnit: Unitless

Note: Value can be positive or negative.

Tonnage of Refrigeration in TR

Tonnage of Refrigeration in TR is the unit of measurement for the cooling capacity of an air refrigeration system, typically used in industrial and commercial applications.

Symbol: Q

Measurement: NAUnit: Unitless

Note: Value can be positive or negative.

Mass of Air

Mass of Air is the amount of air present in a refrigeration system, which affects the cooling performance and overall efficiency of the system.

Symbol: ma

Measurement: Mass Flow RateUnit: kg/min

Note: Value should be greater than 0.

Specific Heat Capacity at Constant Pressure

Specific Heat Capacity at Constant Pressure is the amount of heat required to change the temperature of air in refrigeration systems by one degree Celsius.

Symbol: C_p

Measurement: Specific Heat CapacityUnit: kJ/kg*K

Note: Value can be positive or negative.

Actual End Temp of Isentropic Compression

Actual End Temp of Isentropic Compression is the final temperature of air at the end of an isentropic compression process in air refrigeration systems.

Symbol: Tt^'

Measurement: TemperatureUnit: K

Note: Value can be positive or negative.

Actual Temperature of Rammed Air

Actual temperature of Rammed Air is the temperature of air after it has been compressed and cooled in an air refrigeration system.

Symbol: T2^'

Measurement: TemperatureUnit: K

Note: Value can be positive or negative.

Credits

Created by Rushi Shah

K J Somaiya College of Engineering (K J Somaiya), Mumbai

Rushi Shah has created this Formula and 25+ more formulas!

Verified by Suman Ray Pramanik

Indian Institute of Technology (IIT), Kanpur

Suman Ray Pramanik has verified this Formula and 100+ more formulas!

Other Formulas to find Actual Coefficient of Performance

Go C.O.P. of simple air cycle

COP actual = \frac{T 6 - T5'}{Tt' - T2'}

Go COP of Air Cycle for given Input Power and Tonnage of Refrigeration

COP actual = \frac{210 \cdot Q}{P in \cdot 60}

Other formulas in Air Refrigeration category

Go Energy Performance Ratio of Heat Pump

COP theoretical = \frac{Q delivered}{W per min}

Go Relative Coefficient of Performance

COP relative = \frac{COP actual}{COP theoretical}

Go Theoretical Coefficient of Performance of Refrigerator

COP theoretical = \frac{Q ref}{w}

Go Compression or Expansion Ratio

r p = \frac{P 2}{P 1}

How to Evaluate C.O.P. of simple air evaporative cycle?

C.O.P. of simple air evaporative cycle evaluator uses Actual Coefficient of Performance = (210*Tonnage of Refrigeration in TR)/(Mass of Air*Specific Heat Capacity at Constant Pressure*(Actual End Temp of Isentropic Compression-Actual Temperature of Rammed Air)) to evaluate the Actual Coefficient of Performance, C.O.P. of simple air evaporative cycle formula is defined as a measure of the actual performance of an air evaporative cooling system, which indicates its ability to transfer heat from the air to the water, providing a cooling effect. It is a key parameter in evaluating the efficiency of air evaporative cooling systems. Actual Coefficient of Performance is denoted by COP_actual symbol.

How to evaluate C.O.P. of simple air evaporative cycle using this online evaluator? To use this online evaluator for C.O.P. of simple air evaporative cycle, enter Tonnage of Refrigeration in TR (Q), Mass of Air (ma), Specific Heat Capacity at Constant Pressure (C_p), Actual End Temp of Isentropic Compression (Tt^') & Actual Temperature of Rammed Air (T2^') and hit the calculate button.

FAQs on C.O.P. of simple air evaporative cycle

What is the formula to find C.O.P. of simple air evaporative cycle?

The formula of C.O.P. of simple air evaporative cycle is expressed as Actual Coefficient of Performance = (210*Tonnage of Refrigeration in TR)/(Mass of Air*Specific Heat Capacity at Constant Pressure*(Actual End Temp of Isentropic Compression-Actual Temperature of Rammed Air)). Here is an example- 0.244233 = (210*150)/(2*1005*(350-273)).

How to calculate C.O.P. of simple air evaporative cycle?

With Tonnage of Refrigeration in TR (Q), Mass of Air (ma), Specific Heat Capacity at Constant Pressure (C_p), Actual End Temp of Isentropic Compression (Tt^') & Actual Temperature of Rammed Air (T2^') we can find C.O.P. of simple air evaporative cycle using the formula - Actual Coefficient of Performance = (210*Tonnage of Refrigeration in TR)/(Mass of Air*Specific Heat Capacity at Constant Pressure*(Actual End Temp of Isentropic Compression-Actual Temperature of Rammed Air)).

What are the other ways to Calculate Actual Coefficient of Performance?

Here are the different ways to Calculate Actual Coefficient of Performance-

Actual Coefficient of Performance=(Inside Temperature of Cabin-Actual Temperature at end of Isentropic Expansion)/(Actual End Temp of Isentropic Compression-Actual Temperature of Rammed Air)
Actual Coefficient of Performance=(210*Tonnage of Refrigeration in TR)/(Input Power*60)

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C.O.P. of simple air evaporative cycle Formula

​GoC.O.P. of simple air cycle Formula

​GoCOP of Air Cycle for given Input Power and Tonnage of Refrigeration Formula

C.O.P. of simple air evaporative cycle Example

C.O.P. of simple air evaporative cycle Solution

C.O.P. of simple air evaporative cycle Formula Elements

Credits

Other Formulas to find Actual Coefficient of Performance

Other formulas in Air Refrigeration category

How to Evaluate C.O.P. of simple air evaporative cycle?

FAQs on C.O.P. of simple air evaporative cycle

Variable Name

GoC.O.P. of simple air cycle Formula

GoCOP of Air Cycle for given Input Power and Tonnage of Refrigeration Formula